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27x^2+108x+81=0
a = 27; b = 108; c = +81;
Δ = b2-4ac
Δ = 1082-4·27·81
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(108)-54}{2*27}=\frac{-162}{54} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(108)+54}{2*27}=\frac{-54}{54} =-1 $
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